(0.02-0.3x+x^2)/(0.01+0.4x+4x^2)=3.2

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Solution for (0.02-0.3x+x^2)/(0.01+0.4x+4x^2)=3.2 equation: 



(0.02-0.3x+x^2)/(0.01+0.4x+4x^2)=3.2

We move all terms to the left:

(0.02-0.3x+x^2)/(0.01+0.4x+4x^2)-(3.2)=0



Domain of the equation: (0.01+0.4x+4x^2)!=0

We move all terms containing x to the left, all other terms to the right

4x^2+0.4x!=-0.01

x∈R



We add all the numbers together, and all the variables

(0.02-0.3x+x^2)/(0.01+0.4x+4x^2)-3.2=0

We multiply all the terms by the denominator


(0.02-0.3x+x^2)-(3.2)*(0.01+0.4x+4x^2)=0

We get rid of parentheses

x^2-(3.2)*(0.01+0.4x+4x^2)-0.3x+0.02=0

We move all terms containing x to the left, all other terms to the right

x^2-(3.2)*(0.01+0.4x+4x^2)-0.3x=-0.02

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